2y^2-y+22=0

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Solution for 2y^2-y+22=0 equation:


Simplifying
2y2 + -1y + 22 = 0

Reorder the terms:
22 + -1y + 2y2 = 0

Solving
22 + -1y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
11 + -0.5y + y2 = 0

Move the constant term to the right:

Add '-11' to each side of the equation.
11 + -0.5y + -11 + y2 = 0 + -11

Reorder the terms:
11 + -11 + -0.5y + y2 = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -0.5y + y2 = 0 + -11
-0.5y + y2 = 0 + -11

Combine like terms: 0 + -11 = -11
-0.5y + y2 = -11

The y term is -0.5y.  Take half its coefficient (-0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
-0.5y + 0.0625 + y2 = -11 + 0.0625

Reorder the terms:
0.0625 + -0.5y + y2 = -11 + 0.0625

Combine like terms: -11 + 0.0625 = -10.9375
0.0625 + -0.5y + y2 = -10.9375

Factor a perfect square on the left side:
(y + -0.25)(y + -0.25) = -10.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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